Optimal. Leaf size=202 \[ -\frac {i a b \text {Li}_2\left (-\frac {\left (a^2+b^2\right ) e^{2 i \left (d x^2+c\right )}}{(a+i b)^2}\right )}{2 d^2 \left (a^2+b^2\right )^2}+\frac {b \left (2 a d x^2+b\right ) \log \left (1+\frac {\left (a^2+b^2\right ) e^{2 i \left (c+d x^2\right )}}{(a+i b)^2}\right )}{2 d^2 \left (a^2+b^2\right )^2}-\frac {b x^2}{2 d \left (a^2+b^2\right ) \left (a+b \tan \left (c+d x^2\right )\right )}+\frac {\left (2 a d x^2+b\right )^2}{8 a d^2 (a+i b) \left (a^2+b^2\right )}-\frac {x^4}{4 \left (a^2+b^2\right )} \]
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Rubi [A] time = 0.31, antiderivative size = 202, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {3747, 3733, 3732, 2190, 2279, 2391} \[ -\frac {i a b \text {Li}_2\left (-\frac {\left (a^2+b^2\right ) e^{2 i \left (d x^2+c\right )}}{(a+i b)^2}\right )}{2 d^2 \left (a^2+b^2\right )^2}+\frac {b \left (2 a d x^2+b\right ) \log \left (1+\frac {\left (a^2+b^2\right ) e^{2 i \left (c+d x^2\right )}}{(a+i b)^2}\right )}{2 d^2 \left (a^2+b^2\right )^2}-\frac {b x^2}{2 d \left (a^2+b^2\right ) \left (a+b \tan \left (c+d x^2\right )\right )}+\frac {\left (2 a d x^2+b\right )^2}{8 a d^2 (a+i b) \left (a^2+b^2\right )}-\frac {x^4}{4 \left (a^2+b^2\right )} \]
Antiderivative was successfully verified.
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Rule 2190
Rule 2279
Rule 2391
Rule 3732
Rule 3733
Rule 3747
Rubi steps
\begin {align*} \int \frac {x^3}{\left (a+b \tan \left (c+d x^2\right )\right )^2} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {x}{(a+b \tan (c+d x))^2} \, dx,x,x^2\right )\\ &=-\frac {x^4}{4 \left (a^2+b^2\right )}-\frac {b x^2}{2 \left (a^2+b^2\right ) d \left (a+b \tan \left (c+d x^2\right )\right )}+\frac {\operatorname {Subst}\left (\int \frac {b+2 a d x}{a+b \tan (c+d x)} \, dx,x,x^2\right )}{2 \left (a^2+b^2\right ) d}\\ &=-\frac {x^4}{4 \left (a^2+b^2\right )}+\frac {\left (b+2 a d x^2\right )^2}{8 a (a+i b) \left (a^2+b^2\right ) d^2}-\frac {b x^2}{2 \left (a^2+b^2\right ) d \left (a+b \tan \left (c+d x^2\right )\right )}+\frac {(i b) \operatorname {Subst}\left (\int \frac {e^{2 i (c+d x)} (b+2 a d x)}{(a+i b)^2+\left (a^2+b^2\right ) e^{2 i (c+d x)}} \, dx,x,x^2\right )}{\left (a^2+b^2\right ) d}\\ &=-\frac {x^4}{4 \left (a^2+b^2\right )}+\frac {\left (b+2 a d x^2\right )^2}{8 a (a+i b) \left (a^2+b^2\right ) d^2}+\frac {b \left (b+2 a d x^2\right ) \log \left (1+\frac {\left (a^2+b^2\right ) e^{2 i \left (c+d x^2\right )}}{(a+i b)^2}\right )}{2 \left (a^2+b^2\right )^2 d^2}-\frac {b x^2}{2 \left (a^2+b^2\right ) d \left (a+b \tan \left (c+d x^2\right )\right )}-\frac {(a b) \operatorname {Subst}\left (\int \log \left (1+\frac {\left (a^2+b^2\right ) e^{2 i (c+d x)}}{(a+i b)^2}\right ) \, dx,x,x^2\right )}{\left (a^2+b^2\right )^2 d}\\ &=-\frac {x^4}{4 \left (a^2+b^2\right )}+\frac {\left (b+2 a d x^2\right )^2}{8 a (a+i b) \left (a^2+b^2\right ) d^2}+\frac {b \left (b+2 a d x^2\right ) \log \left (1+\frac {\left (a^2+b^2\right ) e^{2 i \left (c+d x^2\right )}}{(a+i b)^2}\right )}{2 \left (a^2+b^2\right )^2 d^2}-\frac {b x^2}{2 \left (a^2+b^2\right ) d \left (a+b \tan \left (c+d x^2\right )\right )}+\frac {(i a b) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {\left (a^2+b^2\right ) x}{(a+i b)^2}\right )}{x} \, dx,x,e^{2 i \left (c+d x^2\right )}\right )}{2 \left (a^2+b^2\right )^2 d^2}\\ &=-\frac {x^4}{4 \left (a^2+b^2\right )}+\frac {\left (b+2 a d x^2\right )^2}{8 a (a+i b) \left (a^2+b^2\right ) d^2}+\frac {b \left (b+2 a d x^2\right ) \log \left (1+\frac {\left (a^2+b^2\right ) e^{2 i \left (c+d x^2\right )}}{(a+i b)^2}\right )}{2 \left (a^2+b^2\right )^2 d^2}-\frac {i a b \text {Li}_2\left (-\frac {\left (a^2+b^2\right ) e^{2 i \left (c+d x^2\right )}}{(a+i b)^2}\right )}{2 \left (a^2+b^2\right )^2 d^2}-\frac {b x^2}{2 \left (a^2+b^2\right ) d \left (a+b \tan \left (c+d x^2\right )\right )}\\ \end {align*}
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Mathematica [B] time = 6.81, size = 703, normalized size = 3.48 \[ -\frac {\sec ^2\left (c+d x^2\right ) \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )^2 \left (\frac {a \left (i \text {Li}_2\left (e^{2 i \left (d x^2+c+\tan ^{-1}\left (\frac {a}{b}\right )\right )}\right )+i \left (2 \tan ^{-1}\left (\frac {a}{b}\right )-\pi \right ) \left (c+d x^2\right )-2 \left (\tan ^{-1}\left (\frac {a}{b}\right )+c+d x^2\right ) \log \left (1-e^{2 i \left (\tan ^{-1}\left (\frac {a}{b}\right )+c+d x^2\right )}\right )+2 \tan ^{-1}\left (\frac {a}{b}\right ) \log \left (\sin \left (\tan ^{-1}\left (\frac {a}{b}\right )+c+d x^2\right )\right )-\pi \log \left (1+e^{-2 i \left (c+d x^2\right )}\right )+\pi \log \left (\cos \left (c+d x^2\right )\right )\right )}{b \sqrt {\frac {a^2}{b^2}+1}}+e^{i \tan ^{-1}\left (\frac {a}{b}\right )} \left (c+d x^2\right )^2\right )}{2 d^2 (a-i b) (a+i b) \sqrt {\frac {a^2+b^2}{b^2}} \left (a+b \tan \left (c+d x^2\right )\right )^2}-\frac {b c \sec ^2\left (c+d x^2\right ) \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )^2 \left (a \log \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )-b \left (c+d x^2\right )\right )}{d^2 (a-i b) (a+i b) \left (a^2+b^2\right ) \left (a+b \tan \left (c+d x^2\right )\right )^2}+\frac {b^2 \sec ^2\left (c+d x^2\right ) \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )^2 \left (a \log \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )-b \left (c+d x^2\right )\right )}{2 a d^2 (a-i b) (a+i b) \left (a^2+b^2\right ) \left (a+b \tan \left (c+d x^2\right )\right )^2}+\frac {\sec ^2\left (c+d x^2\right ) \left (b^2 \left (c+d x^2\right ) \sin \left (c+d x^2\right )-b^2 c \sin \left (c+d x^2\right )\right ) \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )}{2 a d^2 (a-i b) (a+i b) \left (a+b \tan \left (c+d x^2\right )\right )^2}+\frac {\left (d x^2-c\right ) \left (c+d x^2\right ) \sec ^2\left (c+d x^2\right ) \left (a \cos \left (c+d x^2\right )+b \sin \left (c+d x^2\right )\right )^2}{4 d^2 (a-i b) (a+i b) \left (a+b \tan \left (c+d x^2\right )\right )^2} \]
Warning: Unable to verify antiderivative.
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fricas [B] time = 0.83, size = 806, normalized size = 3.99 \[ \frac {{\left (a^{3} - a b^{2}\right )} d^{2} x^{4} - 2 \, b^{3} d x^{2} + {\left (i \, a b^{2} \tan \left (d x^{2} + c\right ) + i \, a^{2} b\right )} {\rm Li}_2\left (\frac {2 \, {\left (i \, a b - b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} - 2 \, a^{2} - 2 i \, a b - {\left (-2 i \, a^{2} + 4 \, a b + 2 i \, b^{2}\right )} \tan \left (d x^{2} + c\right )}{{\left (a^{2} + b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} + a^{2} + b^{2}} + 1\right ) + {\left (-i \, a b^{2} \tan \left (d x^{2} + c\right ) - i \, a^{2} b\right )} {\rm Li}_2\left (\frac {2 \, {\left (-i \, a b - b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} - 2 \, a^{2} + 2 i \, a b - {\left (2 i \, a^{2} + 4 \, a b - 2 i \, b^{2}\right )} \tan \left (d x^{2} + c\right )}{{\left (a^{2} + b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} + a^{2} + b^{2}} + 1\right ) + 2 \, {\left (a^{2} b d x^{2} + a^{2} b c + {\left (a b^{2} d x^{2} + a b^{2} c\right )} \tan \left (d x^{2} + c\right )\right )} \log \left (-\frac {2 \, {\left (i \, a b - b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} - 2 \, a^{2} - 2 i \, a b - {\left (-2 i \, a^{2} + 4 \, a b + 2 i \, b^{2}\right )} \tan \left (d x^{2} + c\right )}{{\left (a^{2} + b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} + a^{2} + b^{2}}\right ) + 2 \, {\left (a^{2} b d x^{2} + a^{2} b c + {\left (a b^{2} d x^{2} + a b^{2} c\right )} \tan \left (d x^{2} + c\right )\right )} \log \left (-\frac {2 \, {\left (-i \, a b - b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} - 2 \, a^{2} + 2 i \, a b - {\left (2 i \, a^{2} + 4 \, a b - 2 i \, b^{2}\right )} \tan \left (d x^{2} + c\right )}{{\left (a^{2} + b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} + a^{2} + b^{2}}\right ) - {\left (2 \, a^{2} b c - a b^{2} + {\left (2 \, a b^{2} c - b^{3}\right )} \tan \left (d x^{2} + c\right )\right )} \log \left (\frac {{\left (i \, a b + b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} - a^{2} + i \, a b + {\left (i \, a^{2} + i \, b^{2}\right )} \tan \left (d x^{2} + c\right )}{\tan \left (d x^{2} + c\right )^{2} + 1}\right ) - {\left (2 \, a^{2} b c - a b^{2} + {\left (2 \, a b^{2} c - b^{3}\right )} \tan \left (d x^{2} + c\right )\right )} \log \left (\frac {{\left (i \, a b - b^{2}\right )} \tan \left (d x^{2} + c\right )^{2} + a^{2} + i \, a b + {\left (i \, a^{2} + i \, b^{2}\right )} \tan \left (d x^{2} + c\right )}{\tan \left (d x^{2} + c\right )^{2} + 1}\right ) + {\left ({\left (a^{2} b - b^{3}\right )} d^{2} x^{4} + 2 \, a b^{2} d x^{2}\right )} \tan \left (d x^{2} + c\right )}{4 \, {\left ({\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} d^{2} \tan \left (d x^{2} + c\right ) + {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} d^{2}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{{\left (b \tan \left (d x^{2} + c\right ) + a\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.59, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{\left (a +b \tan \left (d \,x^{2}+c \right )\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.26, size = 1008, normalized size = 4.99 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {x^3}{{\left (a+b\,\mathrm {tan}\left (d\,x^2+c\right )\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3}}{\left (a + b \tan {\left (c + d x^{2} \right )}\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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